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* ppl: use session.user_id instead of user.id for user criterion * fix test Co-authored-by: Caleb Doxsey <cdoxsey@pomerium.com>
53 lines
1.1 KiB
Go
53 lines
1.1 KiB
Go
package criteria
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import (
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"github.com/open-policy-agent/opa/ast"
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"github.com/pomerium/pomerium/pkg/policy/generator"
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"github.com/pomerium/pomerium/pkg/policy/parser"
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"github.com/pomerium/pomerium/pkg/policy/rules"
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)
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var usersBody = ast.Body{
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ast.MustParseExpr(`
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session := get_session(input.session.id)
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`),
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ast.MustParseExpr(`
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user_id := session.user_id
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`),
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}
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type usersCriterion struct {
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g *Generator
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}
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func (usersCriterion) DataType() generator.CriterionDataType {
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return CriterionDataTypeStringMatcher
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}
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func (usersCriterion) Name() string {
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return "user"
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}
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func (c usersCriterion) GenerateRule(_ string, data parser.Value) (*ast.Rule, []*ast.Rule, error) {
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r := c.g.NewRule("users")
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r.Body = append(r.Body, usersBody...)
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err := matchString(&r.Body, ast.VarTerm("user_id"), data)
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if err != nil {
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return nil, nil, err
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}
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return r, []*ast.Rule{
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rules.GetSession(),
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}, nil
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}
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// UserIDs returns a Criterion on a user's id.
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func UserIDs(generator *Generator) Criterion {
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return usersCriterion{g: generator}
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}
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func init() {
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Register(UserIDs)
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}
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