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[core] Do not save default internal attributes in template mode

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Candice Bentéjac 2022-10-12 09:49:29 +01:00
parent 930af07966
commit fe3a0764b0
1 changed files with 14 additions and 2 deletions
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16
meshroom/core/graph.py
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@ -1236,14 +1236,14 @@ class Graph(BaseObject):
def getNonDefaultInputAttributes(self):
"""
Instead of getting all the inputs attribute keys, only get the keys of
Instead of getting all the inputs and internal attribute keys, only get the keys of
the attributes whose value is not the default one.
The output attributes, UIDs, parallelization parameters and internal folder are
not relevant for templates, so they are explicitly removed from the returned dictionary.
Returns:
dict: self.toDict() with the output attributes, UIDs, parallelization parameters, internal folder
and input attributes with default values removed
and input/internal attributes with default values removed
"""
graph = self.toDict()
for nodeName in graph.keys():
@ -1251,12 +1251,24 @@ class Graph(BaseObject):
inputKeys = list(graph[nodeName]["inputs"].keys())
internalInputKeys = []
internalInputs = graph[nodeName].get("internalInputs", None)
if internalInputs:
internalInputKeys = list(internalInputs.keys())
for attrName in inputKeys:
attribute = node.attribute(attrName)
# check that attribute is not a link for choice attributes
if attribute.isDefault and not attribute.isLink:
del graph[nodeName]["inputs"][attrName]
for attrName in internalInputKeys:
attribute = node.internalAttribute(attrName)
# check that internal attribute is not a link for choice attributes
if attribute.isDefault and not attribute.isLink:
del graph[nodeName]["internalInputs"][attrName]
del graph[nodeName]["outputs"]
del graph[nodeName]["uids"]
del graph[nodeName]["internalFolder"]